| be misinterpreting what I am saying. Lets look at two things first. The N2O fogger nozzles have jets in them which allow a specific amount of N2O and fuel to be delivered over time. This means that any time the solenoids are opened, you would be able to easily say that 'x' amount of N2O and fuel have been dispensed over a given period of time that it is open. On the other hand, an engine has a variable level of air that it consumes which is proportional to its RPM, throttle position, and boost level. We can simply look at the throttle position as being WOT for sake of this explanation. Lets look at the engine's airflow demand starting from 2000RPM and up. We'll reference this non-N2O dynochart to give us insight into how the engine's airflow demand is breathing air:
 The torque curve very precisely represents the quantity of air entering the engine since it takes air and fuel to make combustion, and the more of it you have, the more force the combustion process will create. At 3000RPM this engine is at 225ft/lbs but by 5000RPM that value has doubled. This means that the airflow demand has also doubled - the engine is simply breathing twice as much air. Since the N2O injection is a static flowrate, the less air demand that the engine has will mean the less air the engine is pulling through the filters and the more of a saturation the N2O will have. This can also be documented by looking at the non-N2O dynorun compared to the N2O injected run below: You can see the dark blue upper line is the 590HP pull around 5500RPM which was N2O sprayed all the time. The green line just below it is 540HP without N2O and around the same RPM. There is a gain of about 40RWHP here with the 60 shot and 60*.82 = 49HP, so we're a little shy of the predicted value, but its still a gain. Now if you compare the torque values of those two runs at 5500RPM, you find that there is about ~580TQ with N2O and ~520TQ without it for a difference of 60ft/lbs. Now here's the zenith of my explanation: If you look at what's going on around 4000RPM with the torque curves, you will find that with N2O there is 470ft/lbs of TQ with N2O, and 340ft/lbs of TQ without it. This is a difference of 130ft/lbs of torque! The reason it is so much more of a difference at lower RPM is because of the saturation of intake air with N2O. This is because the static flowrate that the fogger is producing is more of a shot when the engine's airflow demand is lower. If you look at the horsepower gained at the same 4000RPM level, the non-N2O shot is at 280HP and the N2O shot is at 360HP. That's a difference of 80HP, which falls off to around 40HP at 5500RPM (and even lower if you go beyond that point)..
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